(14x-33)=(10x+45)

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Solution for (14x-33)=(10x+45) equation: 



(14x-33)=(10x+45)

We move all terms to the left:

(14x-33)-((10x+45))=0

We get rid of parentheses

14x-((10x+45))-33=0



We calculate terms in parentheses: -((10x+45)), so:

(10x+45)

We get rid of parentheses

10x+45

Back to the equation:

-(10x+45)



We get rid of parentheses

14x-10x-45-33=0

We add all the numbers together, and all the variables

4x-78=0

We move all terms containing x to the left, all other terms to the right

4x=78

x=78/4

x=19+1/2

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