x2-20x+38=-9x+8

Solution for x2-20x+38=-9x+8 equation:

x2-20x+38=-9x+8

We move all terms to the left:

x2-20x+38-(-9x+8)=0

We add all the numbers together, and all the variables

x^2-20x-(-9x+8)+38=0

We get rid of parentheses

x^2-20x+9x-8+38=0

We add all the numbers together, and all the variables

x^2-11x+30=0

a = 1; b = -11; c = +30;
Δ = b2-4ac
Δ = -112-4·1·30
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*1}=\frac{10}{2}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*1}=\frac{12}{2}
=6
$