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x2-18x-3600=0
We add all the numbers together, and all the variables
x^2-18x-3600=0
a = 1; b = -18; c = -3600;
Δ = b2-4ac
Δ = -182-4·1·(-3600)
Δ = 14724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14724}=\sqrt{36*409}=\sqrt{36}*\sqrt{409}=6\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{409}}{2*1}=\frac{18-6\sqrt{409}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{409}}{2*1}=\frac{18+6\sqrt{409}}{2} $
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