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7n^2-6n-14=21
We move all terms to the left:
7n^2-6n-14-(21)=0
We add all the numbers together, and all the variables
7n^2-6n-35=0
a = 7; b = -6; c = -35;
Δ = b2-4ac
Δ = -62-4·7·(-35)
Δ = 1016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1016}=\sqrt{4*254}=\sqrt{4}*\sqrt{254}=2\sqrt{254}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{254}}{2*7}=\frac{6-2\sqrt{254}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{254}}{2*7}=\frac{6+2\sqrt{254}}{14} $
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