x2+x2=(142)2

Solution for x2+x2=(142)2 equation:

x2+x2=(142)2

We move all terms to the left:

x2+x2-((142)2)=0

determiningTheFunctionDomain
x2+x2-1422=0

We add all the numbers together, and all the variables

2x^2-1422=0

a = 2; b = 0; c = -1422;
Δ = b2-4ac
Δ = 02-4·2·(-1422)
Δ = 11376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11376}=\sqrt{144*79}=\sqrt{144}*\sqrt{79}=12\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{79}}{2*2}=\frac{0-12\sqrt{79}}{4}
=-\frac{12\sqrt{79}}{4}
=-3\sqrt{79}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{79}}{2*2}=\frac{0+12\sqrt{79}}{4}
=\frac{12\sqrt{79}}{4}
=3\sqrt{79}
$