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(9x)2-43x=76
We move all terms to the left:
(9x)2-43x-(76)=0
We add all the numbers together, and all the variables
9x^2-43x-76=0
a = 9; b = -43; c = -76;
Δ = b2-4ac
Δ = -432-4·9·(-76)
Δ = 4585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{4585}}{2*9}=\frac{43-\sqrt{4585}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{4585}}{2*9}=\frac{43+\sqrt{4585}}{18} $
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