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x2+x+23=8x+3
We move all terms to the left:
x2+x+23-(8x+3)=0
We add all the numbers together, and all the variables
x^2+x-(8x+3)+23=0
We get rid of parentheses
x^2+x-8x-3+23=0
We add all the numbers together, and all the variables
x^2-7x+20=0
a = 1; b = -7; c = +20;
Δ = b2-4ac
Δ = -72-4·1·20
Δ = -31
Delta is less than zero, so there is no solution for the equation
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