8(2x-10)+16=32

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Solution for 8(2x-10)+16=32 equation: 



8(2x-10)+16=32

We move all terms to the left:

8(2x-10)+16-(32)=0

We add all the numbers together, and all the variables

8(2x-10)-16=0

We multiply parentheses

16x-80-16=0

We add all the numbers together, and all the variables

16x-96=0

We move all terms containing x to the left, all other terms to the right

16x=96

x=96/16

x=6

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