3(b+5)=42(b-5)

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Solution for 3(b+5)=42(b-5) equation:



3(b+5)=42(b-5)
We move all terms to the left:
3(b+5)-(42(b-5))=0
We multiply parentheses
3b-(42(b-5))+15=0
We calculate terms in parentheses: -(42(b-5)), so:
42(b-5)
We multiply parentheses
42b-210
Back to the equation:
-(42b-210)
We get rid of parentheses
3b-42b+210+15=0
We add all the numbers together, and all the variables
-39b+225=0
We move all terms containing b to the left, all other terms to the right
-39b=-225
b=-225/-39
b=5+10/13

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