x2+6x-10/17=169.412

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Solution for x2+6x-10/17=169.412 equation:



x2+6x-10/17=169.412
We move all terms to the left:
x2+6x-10/17-(169.412)=0
We add all the numbers together, and all the variables
x^2+6x-169.412-10/17=0
We multiply all the terms by the denominator
x^2*17+6x*17-10-(169.412)*17=0
We add all the numbers together, and all the variables
x^2*17+6x*17-2890.004=0
Wy multiply elements
17x^2+102x-2890.004=0
a = 17; b = 102; c = -2890.004;
Δ = b2-4ac
Δ = 1022-4·17·(-2890.004)
Δ = 206924.272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-\sqrt{206924.272}}{2*17}=\frac{-102-\sqrt{206924.272}}{34} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+\sqrt{206924.272}}{2*17}=\frac{-102+\sqrt{206924.272}}{34} $

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