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7x(3x-10)=0
We multiply parentheses
21x^2-70x=0
a = 21; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·21·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*21}=\frac{0}{42} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*21}=\frac{140}{42} =3+1/3 $
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