x2+4x-25=100

Solution for x2+4x-25=100 equation:

x2+4x-25=100

We move all terms to the left:

x2+4x-25-(100)=0

We add all the numbers together, and all the variables

x^2+4x-125=0

a = 1; b = 4; c = -125;
Δ = b2-4ac
Δ = 42-4·1·(-125)
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{129}}{2*1}=\frac{-4-2\sqrt{129}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{129}}{2*1}=\frac{-4+2\sqrt{129}}{2}
$