4(x+2)(x+3)=35

Solution for 4(x+2)(x+3)=35 equation:

4(x+2)(x+3)=35

We move all terms to the left:

4(x+2)(x+3)-(35)=0

We multiply parentheses ..

4(+x^2+3x+2x+6)-35=0

We multiply parentheses

4x^2+12x+8x+24-35=0

We add all the numbers together, and all the variables

4x^2+20x-11=0

a = 4; b = 20; c = -11;
Δ = b2-4ac
Δ = 202-4·4·(-11)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-24}{2*4}=\frac{-44}{8}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+24}{2*4}=\frac{4}{8}
=1/2
$