x2+3x=x2-2x+10

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Solution for x2+3x=x2-2x+10 equation: 



x2+3x=x2-2x+10

We move all terms to the left:

x2+3x-(x2-2x+10)=0

We add all the numbers together, and all the variables

-(+x^2-2x+10)+x2+3x=0

We add all the numbers together, and all the variables

x^2-(+x^2-2x+10)+3x=0

We get rid of parentheses

x^2-x^2+2x+3x-10=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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