5+4(z+9)=-3+2(z-1)

Solution for 5+4(z+9)=-3+2(z-1) equation:

5+4(z+9)=-3+2(z-1)

We move all terms to the left:

5+4(z+9)-(-3+2(z-1))=0

We multiply parentheses

4z-(-3+2(z-1))+36+5=0


We calculate terms in parentheses: -(-3+2(z-1)), so:

-3+2(z-1)

determiningTheFunctionDomain
2(z-1)-3

We multiply parentheses

2z-2-3

We add all the numbers together, and all the variables

2z-5

Back to the equation:

-(2z-5)


We add all the numbers together, and all the variables

4z-(2z-5)+41=0

We get rid of parentheses

4z-2z+5+41=0

We add all the numbers together, and all the variables

2z+46=0

We move all terms containing z to the left, all other terms to the right

2z=-46

z=-46/2

z=-23