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-2x(x+3)+5x=-39
We move all terms to the left:
-2x(x+3)+5x-(-39)=0
We add all the numbers together, and all the variables
5x-2x(x+3)+39=0
We multiply parentheses
-2x^2+5x-6x+39=0
We add all the numbers together, and all the variables
-2x^2-1x+39=0
a = -2; b = -1; c = +39;
Δ = b2-4ac
Δ = -12-4·(-2)·39
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{313}}{2*-2}=\frac{1-\sqrt{313}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{313}}{2*-2}=\frac{1+\sqrt{313}}{-4} $
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