x2+35x-900=0

Solution for x2+35x-900=0 equation:

x2+35x-900=0

We add all the numbers together, and all the variables

x^2+35x-900=0

a = 1; b = 35; c = -900;
Δ = b2-4ac
Δ = 352-4·1·(-900)
Δ = 4825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4825}=\sqrt{25*193}=\sqrt{25}*\sqrt{193}=5\sqrt{193}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5\sqrt{193}}{2*1}=\frac{-35-5\sqrt{193}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5\sqrt{193}}{2*1}=\frac{-35+5\sqrt{193}}{2}
$