5(r+3)-2(r-4)=53

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Solution for 5(r+3)-2(r-4)=53 equation: 



5(r+3)-2(r-4)=53

We move all terms to the left:

5(r+3)-2(r-4)-(53)=0

We multiply parentheses

5r-2r+15+8-53=0

We add all the numbers together, and all the variables

3r-30=0

We move all terms containing r to the left, all other terms to the right

3r=30

r=30/3

r=10

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