x2+35x+150=0

Solution for x2+35x+150=0 equation:

x2+35x+150=0

We add all the numbers together, and all the variables

x^2+35x+150=0

a = 1; b = 35; c = +150;
Δ = b2-4ac
Δ = 352-4·1·150
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-25}{2*1}=\frac{-60}{2}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+25}{2*1}=\frac{-10}{2}
=-5
$