6+6(3-2z)=72

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Solution for 6+6(3-2z)=72 equation: 



6+6(3-2z)=72

We move all terms to the left:

6+6(3-2z)-(72)=0

We add all the numbers together, and all the variables

6(-2z+3)+6-72=0

We add all the numbers together, and all the variables

6(-2z+3)-66=0

We multiply parentheses

-12z+18-66=0

We add all the numbers together, and all the variables

-12z-48=0

We move all terms containing z to the left, all other terms to the right

-12z=48

z=48/-12

z=-4

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