x2+32x+240=0

Solution for x2+32x+240=0 equation:

x2+32x+240=0

We add all the numbers together, and all the variables

x^2+32x+240=0

a = 1; b = 32; c = +240;
Δ = b2-4ac
Δ = 322-4·1·240
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*1}=\frac{-40}{2}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*1}=\frac{-24}{2}
=-12
$