1/2z+6=3/2(z+6

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Solution for 1/2z+6=3/2(z+6 equation: 



1/2z+6=3/2(z+6

We move all terms to the left:

1/2z+6-(3/2(z+6)=0



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R





Domain of the equation: 2(z+6)+6!=0

We move all terms containing z to the left, all other terms to the right

2(z+6)!=-6

z∈R



We calculate fractions


(2z(z+6)/(4z^2(z+6)+(-(3*2z)/(4z^2(z+6)=0



We calculate terms in parentheses: +(2z(z+6)/(4z^2(z+6)+(-(3*2z)/(4z^2(z+6), so:

2z(z+6)/(4z^2(z+6)+(-(3*2z)/(4z^2(z+6

We can not solve this equation

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