x2+29x+100=0

Solution for x2+29x+100=0 equation:

x2+29x+100=0

We add all the numbers together, and all the variables

x^2+29x+100=0

a = 1; b = 29; c = +100;
Δ = b2-4ac
Δ = 292-4·1·100
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-21}{2*1}=\frac{-50}{2}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+21}{2*1}=\frac{-8}{2}
=-4
$