2(t-4)4=3-(3t+1)

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Solution for 2(t-4)4=3-(3t+1) equation: 



2(t-4)4=3-(3t+1)

We move all terms to the left:

2(t-4)4-(3-(3t+1))=0

We multiply parentheses

8t-(3-(3t+1))-32=0



We calculate terms in parentheses: -(3-(3t+1)), so:

3-(3t+1)

determiningTheFunctionDomain
-(3t+1)+3

We get rid of parentheses

-3t-1+3

We add all the numbers together, and all the variables

-3t+2

Back to the equation:

-(-3t+2)



We get rid of parentheses

8t+3t-2-32=0

We add all the numbers together, and all the variables

11t-34=0

We move all terms containing t to the left, all other terms to the right

11t=34

t=34/11

t=3+1/11

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