22=6(2r-5)

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Solution for 22=6(2r-5) equation: 



22=6(2r-5)

We move all terms to the left:

22-(6(2r-5))=0



We calculate terms in parentheses: -(6(2r-5)), so:

6(2r-5)

We multiply parentheses

12r-30

Back to the equation:

-(12r-30)



We get rid of parentheses

-12r+30+22=0

We add all the numbers together, and all the variables

-12r+52=0

We move all terms containing r to the left, all other terms to the right

-12r=-52

r=-52/-12

r=4+1/3

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