x2+28x+96=0

Solution for x2+28x+96=0 equation:

x2+28x+96=0

We add all the numbers together, and all the variables

x^2+28x+96=0

a = 1; b = 28; c = +96;
Δ = b2-4ac
Δ = 282-4·1·96
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-20}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+20}{2*1}=\frac{-8}{2}
=-4
$