4(k-5)=3(2-3k)

Solution for 4(k-5)=3(2-3k) equation:

4(k-5)=3(2-3k)

We move all terms to the left:

4(k-5)-(3(2-3k))=0

We add all the numbers together, and all the variables

4(k-5)-(3(-3k+2))=0

We multiply parentheses

4k-(3(-3k+2))-20=0


We calculate terms in parentheses: -(3(-3k+2)), so:

3(-3k+2)

We multiply parentheses

-9k+6

Back to the equation:

-(-9k+6)


We get rid of parentheses

4k+9k-6-20=0

We add all the numbers together, and all the variables

13k-26=0

We move all terms containing k to the left, all other terms to the right

13k=26

k=26/13

k=2