9(12+14z)=3(6z-18)

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Solution for 9(12+14z)=3(6z-18) equation: 



9(12+14z)=3(6z-18)

We move all terms to the left:

9(12+14z)-(3(6z-18))=0

We add all the numbers together, and all the variables

9(14z+12)-(3(6z-18))=0

We multiply parentheses

126z-(3(6z-18))+108=0



We calculate terms in parentheses: -(3(6z-18)), so:

3(6z-18)

We multiply parentheses

18z-54

Back to the equation:

-(18z-54)



We get rid of parentheses

126z-18z+54+108=0

We add all the numbers together, and all the variables

108z+162=0

We move all terms containing z to the left, all other terms to the right

108z=-162

z=-162/108

z=-1+1/2

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