x2+27x+152=0

Solution for x2+27x+152=0 equation:

x2+27x+152=0

We add all the numbers together, and all the variables

x^2+27x+152=0

a = 1; b = 27; c = +152;
Δ = b2-4ac
Δ = 272-4·1·152
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-11}{2*1}=\frac{-38}{2}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+11}{2*1}=\frac{-16}{2}
=-8
$