6(x-5)=5(x+2)-40.

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Solution for 6(x-5)=5(x+2)-40. equation: 



6(x-5)=5(x+2)-40.

We move all terms to the left:

6(x-5)-(5(x+2)-40.)=0

We multiply parentheses

6x-(5(x+2)-40.)-30=0



We calculate terms in parentheses: -(5(x+2)-40.), so:

5(x+2)-40.

We add all the numbers together, and all the variables

5(x+2)-40

We multiply parentheses

5x+10-40

We add all the numbers together, and all the variables

5x-30

Back to the equation:

-(5x-30)



We get rid of parentheses

6x-5x+30-30=0

We add all the numbers together, and all the variables

x=0

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