x2+24x-6480=0

Solution for x2+24x-6480=0 equation:

x2+24x-6480=0

We add all the numbers together, and all the variables

x^2+24x-6480=0

a = 1; b = 24; c = -6480;
Δ = b2-4ac
Δ = 242-4·1·(-6480)
Δ = 26496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26496}=\sqrt{576*46}=\sqrt{576}*\sqrt{46}=24\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24\sqrt{46}}{2*1}=\frac{-24-24\sqrt{46}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24\sqrt{46}}{2*1}=\frac{-24+24\sqrt{46}}{2}
$