2/3x-9=16x+4

Solution for 2/3x-9=16x+4 equation:

2/3x-9=16x+4

We move all terms to the left:

2/3x-9-(16x+4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-16x-4-9=0

We multiply all the terms by the denominator


-16x*3x-4*3x-9*3x+2=0

Wy multiply elements

-48x^2-12x-27x+2=0

We add all the numbers together, and all the variables

-48x^2-39x+2=0

a = -48; b = -39; c = +2;
Δ = b2-4ac
Δ = -392-4·(-48)·2
Δ = 1905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1905}}{2*-48}=\frac{39-\sqrt{1905}}{-96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1905}}{2*-48}=\frac{39+\sqrt{1905}}{-96}
$