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x2+20x-384=0
We add all the numbers together, and all the variables
x^2+20x-384=0
a = 1; b = 20; c = -384;
Δ = b2-4ac
Δ = 202-4·1·(-384)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-44}{2*1}=\frac{-64}{2} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+44}{2*1}=\frac{24}{2} =12 $
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