3(2-3t)=4(t-5)

Solution for 3(2-3t)=4(t-5) equation:

3(2-3t)=4(t-5)

We move all terms to the left:

3(2-3t)-(4(t-5))=0

We add all the numbers together, and all the variables

3(-3t+2)-(4(t-5))=0

We multiply parentheses

-9t-(4(t-5))+6=0


We calculate terms in parentheses: -(4(t-5)), so:

4(t-5)

We multiply parentheses

4t-20

Back to the equation:

-(4t-20)


We get rid of parentheses

-9t-4t+20+6=0

We add all the numbers together, and all the variables

-13t+26=0

We move all terms containing t to the left, all other terms to the right

-13t=-26

t=-26/-13

t=+2