x2+18x-95=0

Solution for x2+18x-95=0 equation:

x2+18x-95=0

We add all the numbers together, and all the variables

x^2+18x-95=0

a = 1; b = 18; c = -95;
Δ = b2-4ac
Δ = 182-4·1·(-95)
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-8\sqrt{11}}{2*1}=\frac{-18-8\sqrt{11}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+8\sqrt{11}}{2*1}=\frac{-18+8\sqrt{11}}{2}
$