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x2+15x=43.75
We move all terms to the left:
x2+15x-(43.75)=0
We add all the numbers together, and all the variables
x^2+15x-43.75=0
a = 1; b = 15; c = -43.75;
Δ = b2-4ac
Δ = 152-4·1·(-43.75)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-20}{2*1}=\frac{-35}{2} =-17+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+20}{2*1}=\frac{5}{2} =2+1/2 $
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