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x2+15x-2850=0
We add all the numbers together, and all the variables
x^2+15x-2850=0
a = 1; b = 15; c = -2850;
Δ = b2-4ac
Δ = 152-4·1·(-2850)
Δ = 11625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11625}=\sqrt{25*465}=\sqrt{25}*\sqrt{465}=5\sqrt{465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{465}}{2*1}=\frac{-15-5\sqrt{465}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{465}}{2*1}=\frac{-15+5\sqrt{465}}{2} $
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