2(3x+9)=40+28

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Solution for 2(3x+9)=40+28 equation: 



2(3x+9)=40+28

We move all terms to the left:

2(3x+9)-(40+28)=0

We add all the numbers together, and all the variables

2(3x+9)-68=0

We multiply parentheses

6x+18-68=0

We add all the numbers together, and all the variables

6x-50=0

We move all terms containing x to the left, all other terms to the right

6x=50

x=50/6

x=8+1/3

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