x2+12x-20=6x-14

Solution for x2+12x-20=6x-14 equation:

x2+12x-20=6x-14

We move all terms to the left:

x2+12x-20-(6x-14)=0

We add all the numbers together, and all the variables

x^2+12x-(6x-14)-20=0

We get rid of parentheses

x^2+12x-6x+14-20=0

We add all the numbers together, and all the variables

x^2+6x-6=0

a = 1; b = 6; c = -6;
Δ = b2-4ac
Δ = 62-4·1·(-6)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{15}}{2*1}=\frac{-6-2\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{15}}{2*1}=\frac{-6+2\sqrt{15}}{2}
$