x2+11x+121=x+96

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Solution for x2+11x+121=x+96 equation: 



x2+11x+121=x+96

We move all terms to the left:

x2+11x+121-(x+96)=0

We add all the numbers together, and all the variables

x^2+11x-(x+96)+121=0

We get rid of parentheses

x^2+11x-x-96+121=0

We add all the numbers together, and all the variables

x^2+10x+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-10}{2}=-5$

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