35=7/4y-13

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Solution for 35=7/4y-13 equation: 



35=7/4y-13

We move all terms to the left:

35-(7/4y-13)=0



Domain of the equation: 4y-13)!=0

y∈R



We get rid of parentheses

-7/4y+13+35=0

We multiply all the terms by the denominator


13*4y+35*4y-7=0

Wy multiply elements

52y+140y-7=0

We add all the numbers together, and all the variables

192y-7=0

We move all terms containing y to the left, all other terms to the right

192y=7

y=7/192

y=7/192

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