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x2+10x+15=3x+3
We move all terms to the left:
x2+10x+15-(3x+3)=0
We add all the numbers together, and all the variables
x^2+10x-(3x+3)+15=0
We get rid of parentheses
x^2+10x-3x-3+15=0
We add all the numbers together, and all the variables
x^2+7x+12=0
a = 1; b = 7; c = +12;
Δ = b2-4ac
Δ = 72-4·1·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*1}=\frac{-8}{2} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*1}=\frac{-6}{2} =-3 $
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