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-4x(x-6)=20
We move all terms to the left:
-4x(x-6)-(20)=0
We multiply parentheses
-4x^2+24x-20=0
a = -4; b = 24; c = -20;
Δ = b2-4ac
Δ = 242-4·(-4)·(-20)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-16}{2*-4}=\frac{-40}{-8} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+16}{2*-4}=\frac{-8}{-8} =1 $
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