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x2+0x-0.25=0

We add all the numbers together, and all the variables

x^2+x-0.25=0

a = 1; b = 1; c = -0.25;

Δ = b^{2}-4ac

Δ = 1^{2}-4·1·(-0.25)

Δ = 2

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{2}}{2*1}=\frac{-1-\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{2}}{2*1}=\frac{-1+\sqrt{2}}{2} $

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