2x2+5x-8=0

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Solution for 2x2+5x-8=0 equation:

2x^2+5x-8=0
a = 2; b = 5; c = -8;Δ = b2-4acΔ = 52-4·2·(-8)Δ = 89The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{89}}{2*2}=\frac{-5-\sqrt{89}}{4}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{89}}{2*2}=\frac{-5+\sqrt{89}}{4}$

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