2x2+5x-8=0

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Solution for 2x2+5x-8=0 equation:



2x^2+5x-8=0
a = 2; b = 5; c = -8;
Δ = b2-4ac
Δ = 52-4·2·(-8)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{89}}{2*2}=\frac{-5-\sqrt{89}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{89}}{2*2}=\frac{-5+\sqrt{89}}{4} $

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