x2+0,011295x-0,00110691=0

Solution for x2+0,011295x-0,00110691=0 equation:

x2+0.011295x-0.00110691=0

We add all the numbers together, and all the variables

x^2+0.011295x-0.00110691=0

a = 1; b = 0.011295; c = -0.00110691;
Δ = b2-4ac
Δ = 0.0112952-4·1·(-0.00110691)
Δ = 0.004555217025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.011295)-\sqrt{0.004555217025}}{2*1}=\frac{-0.011295-\sqrt{0.004555217025}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.011295)+\sqrt{0.004555217025}}{2*1}=\frac{-0.011295+\sqrt{0.004555217025}}{2}
$