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x2+0.01272x-0.00110677=0
We add all the numbers together, and all the variables
x^2+0.01272x-0.00110677=0
a = 1; b = 0.01272; c = -0.00110677;
Δ = b2-4ac
Δ = 0.012722-4·1·(-0.00110677)
Δ = 0.0045888784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.01272)-\sqrt{0.0045888784}}{2*1}=\frac{-0.01272-\sqrt{0.0045888784}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.01272)+\sqrt{0.0045888784}}{2*1}=\frac{-0.01272+\sqrt{0.0045888784}}{2} $
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