x2+(x+2)2=580

Solution for x2+(x+2)2=580 equation:

x2+(x+2)2=580

We move all terms to the left:

x2+(x+2)2-(580)=0

We add all the numbers together, and all the variables

x^2+(x+2)2-580=0

We multiply parentheses

x^2+2x+4-580=0

We add all the numbers together, and all the variables

x^2+2x-576=0

a = 1; b = 2; c = -576;
Δ = b2-4ac
Δ = 22-4·1·(-576)
Δ = 2308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2308}=\sqrt{4*577}=\sqrt{4}*\sqrt{577}=2\sqrt{577}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{577}}{2*1}=\frac{-2-2\sqrt{577}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{577}}{2*1}=\frac{-2+2\sqrt{577}}{2}
$