3(3-2)=2(c-6)

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Solution for 3(3-2)=2(c-6) equation: 



3(3-2)=2(c-6)

We move all terms to the left:

3(3-2)-(2(c-6))=0

We add all the numbers together, and all the variables

-(2(c-6))+31=0



We calculate terms in parentheses: -(2(c-6)), so:

2(c-6)

We multiply parentheses

2c-12

Back to the equation:

-(2c-12)



We get rid of parentheses

-2c+12+31=0

We add all the numbers together, and all the variables

-2c+43=0

We move all terms containing c to the left, all other terms to the right

-2c=-43

c=-43/-2

c=21+1/2

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