3+3(3x-5)=7-3(2x+1)

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Solution for 3+3(3x-5)=7-3(2x+1) equation: 



3+3(3x-5)=7-3(2x+1)

We move all terms to the left:

3+3(3x-5)-(7-3(2x+1))=0

We multiply parentheses

9x-(7-3(2x+1))-15+3=0



We calculate terms in parentheses: -(7-3(2x+1)), so:

7-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+7

We multiply parentheses

-6x-3+7

We add all the numbers together, and all the variables

-6x+4

Back to the equation:

-(-6x+4)



We add all the numbers together, and all the variables

9x-(-6x+4)-12=0

We get rid of parentheses

9x+6x-4-12=0

We add all the numbers together, and all the variables

15x-16=0

We move all terms containing x to the left, all other terms to the right

15x=16

x=16/15

x=1+1/15

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